-490t^2+1260t-810=0

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Solution for -490t^2+1260t-810=0 equation: 



-490t^2+1260t-810=0

a = -490; b = 1260; c = -810;
Δ = b2-4ac
Δ = 12602-4·(-490)·(-810)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-1260}{-980}=1+2/7$

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